horsepower & torque (question for adsayer maybe)

  1. #1
    ok, I was told.....

    bhp= lbft of torque x rpm / 5252

    1.1 (mpi) engine says it's got 70lbft of torque

    peak power is at 5500 rpm

    so

    70lb x 5500rpm / 5252 = 73.30 bhp

    to be 60bhp according to that equation it would have to be

    70lbs x 4500rpm / 5252 = 59.97.

    is it that the engine has 73hp, but it loses 13hp through the gearbox, driveshafts etc, or that equation just doesn't work with tu engines.
  2. #2
    I think you're confusing the RPM range of where peak power and peak torque are achieved, as they're rarely identical.

    If your engine has "70lbs of torque" it will be at a specific RPM range. Your last calculation is just a guess, where there happens to be a calculation which equals to 60bhp. So your second to last calculation is incorrect, as you've mistaken peak power's RPM range to be equal to peak torque's RPM range, hence the increased calculation of BHP you've got. At 5500rpm, your engine will have less than 70lbs of torque, but due to the amount spreading to a higer RPM range, max BHP is achieved.
  3. #3
    toad has it bang on there. peak torque and power do not usually occur at the same engine rpm.
  4. #4
    yeah, peak torque is at 3500 rpm. So your saying torque goes down from there.
  5. #5
    If peak torque is at 3500rpm, then yes, it will begin to drop off after then. Depending on how quickly it drops off will determine your max BHP rpm.
  6. #6
    yeah, so it would be producing something around 57 lb ft of torque at 5500rpm to work out at 60 bhp
  7. #7
    just use a dyno easier lol
  8. #8
    I think you've got it.
  9. #9
    Cool. Thanks.